Materials Data on Be3Cd4Si3TeO12 by Materials Project

Abstract

Be3Cd4Si3TeO12 crystallizes in the cubic P-43n space group. The structure is three-dimensional. Be2+ is bonded to four equivalent O2- atoms to form BeO4 tetrahedra that share corners with four equivalent SiO4 tetrahedra. All Be–O bond lengths are 1.65 Å. Cd2+ is bonded in a 3-coordinate geometry to one Te2- and three equivalent O2- atoms. The Cd–Te bond length is 2.78 Å. All Cd–O bond lengths are 2.25 Å. Si4+ is bonded to four equivalent O2- atoms to form SiO4 tetrahedra that share corners with four equivalent BeO4 tetrahedra. All Si–O bond lengths are 1.65 Å. Te2- is bonded in a tetrahedral geometry to four equivalent Cd2+ atoms. O2- is bonded in a 3-coordinate geometry to one Be2+, one Cd2+, and one Si4+ atom.